Nylon-`5-10`can be prepared by:

Options

A. `H_(2)N(CH_(2))_(5)NH_(2)+` Decanoic acid (Sebacic acid)
B. `HOOC(CH_(2)_(3)COOH+H_(2)N(CH_(2))_(10)NH_(2)`
C. `H_(2)N(CH_(2)_(6)NH_(2)+HOOC(CH_(2))_(8)COOH`
D. `H_(2)N(CH_(2))_(10)NH_(2)+HOOC(CH_(2))_(4)COOH`

Explanation

To prepare Nylon-5,10, we need to follow a series of steps involving the reactants and the reaction process. Here’s a step-by-step breakdown of the preparation:

### Step 1: Identify the Reactants
Nylon-5,10 is synthesized from two key reactants:
- **Pentamethylenediamine** (also known as 1,5-diaminopentane)
- **Sebacic acid** (also known as decanedioic acid)

### Step 2: Understand the Structure of the Reactants
- **Pentamethylenediamine** has the formula NH2(CH2)5NH2. It contains two amine groups (–NH2) and a five-carbon chain.
- **Sebacic acid** has the formula HOOC(CH2)8COOH. It is a dicarboxylic acid with a ten-carbon chain.

### Step 3: Reaction Mechanism
The reaction between pentamethylenediamine and sebacic acid is a condensation reaction. In this reaction:
- The amine groups from pentamethylenediamine react with the carboxylic acid groups from sebacic acid.
- During the reaction, a molecule of water (H2O) is eliminated.

### Step 4: Formation of Nylon-5,10
The resulting polymer, Nylon-5,10, is formed by the repeated units of the amide linkages created from the reaction of the amine and carboxylic acid groups. The general structure of the resulting polymer can be represented as:
- [-NH(CH2)5NHCO(CH2)8CO-]n

### Step 5: Conclusion
Thus, Nylon-5,10 is prepared through the condensation polymerization of pentamethylenediamine and sebacic acid.

### Final Answer
Nylon-5,10 can be prepared from pentamethylenediamine and sebacic acid.

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