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In E. coli DNA, AT//GC ratio is 0.93. If...

In `E. coli DNA,` `AT//GC` ratio is `0.93`. If the nimber of moles of adenine in its `DNA` sample is `465,000,` calculate the number of moles of guanine present.

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The number of moles of adenine should be equal to those of thymine, `(A+T)=930,000. "Since", A+T//G+C=0.93,(G+C)=1,000,000`. Therefore,the number of moles of guanine should be `1,000,000//2=500,000`
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