A mixture of three protiens, `(A)` (pepsin), `(B)` (haemo-globin), and `(C )` (lysozyme) was seperated by elctrophoresis method at `pH=7`. The `pH` at isoelectric point `(pI)` of the proteins are `pI` of `(A)`, `(B)`, and `(C )` which are `1.1,6.7`, and `11.0`, respectively. which of the statement are correct?

Options

A. Pepsin (A) will migrate to the cathode.
B. Lysozyme (C ) will migrate to the anode.
C. Haemoglobon will not migrate.
D. At pH=7, (A) and (C ) would precipitate out while (B) would remain in the solution.

Explanation

To solve the problem, we need to analyze the behavior of the three proteins (pepsin, hemoglobin, and lysozyme) during electrophoresis at pH 7, considering their isoelectric points (pI).

### Step-by-step Solution:

1. **Understanding Isoelectric Point (pI)**:
- The isoelectric point (pI) is the pH at which a protein has no net charge and does not migrate in an electric field.
- Proteins will migrate towards the electrode of opposite charge when they are charged.

2. **Identifying the pI of Each Protein**:
- Pepsin (A): pI = 1.1 (acidic)
- Hemoglobin (B): pI = 6.7 (neutral)
- Lysozyme (C): pI = 11.0 (basic)

3. **Analyzing Protein Behavior at pH 7**:
- **Pepsin (A)**:
- At pH 7, which is higher than its pI (1.1), pepsin will carry a negative charge and will migrate towards the cathode (negative electrode).
- **Hemoglobin (B)**:
- At pH 7, which is very close to its pI (6.7), hemoglobin will be nearly neutral and will not migrate significantly.
- **Lysozyme (C)**:
- At pH 7, which is lower than its pI (11.0), lysozyme will carry a positive charge and will migrate towards the anode (positive electrode).

4. **Conclusion on Migration**:
- Pepsin (A) migrates towards the cathode.
- Hemoglobin (B) does not migrate.
- Lysozyme (C) migrates towards the anode.

5. **Solubility at pH 7**:
- Proteins are least soluble near their isoelectric point.
- Since hemoglobin's pI is 6.7, it will precipitate out of solution at pH 7.
- Pepsin (A) and lysozyme (C) will remain soluble since their pIs are far from 7.

### Summary of Correct Statements:
- Pepsin (A) will migrate to the cathode.
- Hemoglobin (B) will not migrate.
- Lysozyme (C) will migrate to the anode.
- Hemoglobin (B) will precipitate out of solution at pH 7.