Home
Class 12
CHEMISTRY
Statement I: D-2-Deoxyglucose reacts wit...

Statement I: `D-2-`Deoxyglucose reacts with `3 mol PhNHNH_(2)` and form an osazone.
Statement II: `D-2-`Deoxyglucose has no
`(C-OH)` group `alpha-` to the `(C=O)` group.

A

Statement `I` is true, Statement `II` is true, Statements `II` is the correct explanation of Statement `I`.

B

Statement `I` is true, Statement `II` is true, Statement `II` is not the correct explanation of Statement `I`.

C

Statement `I` is true, Statement `II` is false.

D

Statement `I` is false, Statement `II` is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we will analyze both statements regarding D-2-Deoxyglucose and its behavior with phenylhydrazine. ### Step-by-Step Solution: 1. **Understanding D-2-Deoxyglucose**: - D-2-Deoxyglucose is a derivative of glucose where the hydroxyl group (-OH) at the second carbon is replaced by a hydrogen atom (-H). - Its structure can be represented as: ``` CHO - C - H - C - OH - C - OH - CH2OH ``` - The carbonyl group (C=O) is located at the first carbon (C1). 2. **Analyzing Statement I**: - Statement I claims that D-2-Deoxyglucose reacts with 3 moles of phenylhydrazine to form an osazone. - In reality, osazone formation occurs when a reducing sugar reacts with phenylhydrazine. For glucose and its derivatives, including D-2-Deoxyglucose, only 2 moles of phenylhydrazine are required to form the osazone. - Therefore, **Statement I is false**. 3. **Analyzing Statement II**: - Statement II claims that D-2-Deoxyglucose has no hydroxyl group (-OH) alpha to the carbonyl group (C=O). - In the structure of D-2-Deoxyglucose, the carbon adjacent to the carbonyl (C1) is C2, which has a hydrogen atom instead of a hydroxyl group. - Thus, there is indeed no -OH group at the alpha position relative to the carbonyl group. - Therefore, **Statement II is true**. 4. **Conclusion**: - Based on the analysis, we conclude that Statement I is false, and Statement II is true. ### Final Answer: - Statement I: False - Statement II: True
Promotional Banner

Topper's Solved these Questions

  • BIOMOLECULES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Single Correct )|5 Videos

  • BIOMOLECULES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Assertion-Reasoning)|1 Videos

  • BIOMOLECULES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Single Correcttype)|80 Videos

  • AROMATIC COMPOUNDS AND ALKYL AND ARYL HALIDES

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective Type|4 Videos

  • CARBOXYLIC ACIDS AND THEIR DERIVATIVES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Analytical And Descriptive)|34 Videos

Similar Questions

Explore conceptually related problems

How manty moles of (C ) react with 1 mol PhNHNH_(2)

Statement I: D-3 Deoxyglucose has gfour chiral C atoms. Statement II: It exists in eight stereoisomers.

Statement-1: Al forms H_(2) when reacts with NaOH. Statement-2: Al_(2)O_(3) is amphoteric by nature. Statement-3: Al_(2)O_(3) is a neutral oxide.

Statement-1: O_(3) reacts with KOH and forms a paramagnetic compound. Statement-2: KO_(3) is paramagnetic. Statement-3: O_(2) gives O_(2)^(-) when heated with Na//NH_(3)

Write the structures obtained by the epimerisation of alpha-D -gluocose at C-2,C-3 , and C-4(OH) groups.

Which is true statement about D_(2)O and H_(2)O ?

Statement-I : Li_(2)SO_(4) do not form double salt like alum. Statement-II : Li reacts with NH_(3) gas to form LiNH_(2)

a. Statement- 1 and Statement- 2 are true, and state-ment- 2 is the correct explanation of Statement- 1. b. Statement- 1 and Statement- 2 are true but Statement- 2 is not the correct explanation of Statement- 1. c. Statement- 1 is true and Statement- 2 is false. d. Statement- 1 is false and Statement- 2 is true. e. Statement- 1 is false and Statement- 2 is false. Statement- 1: Compound (I) is formed not (II). and Statement- 2: Due to the reduction of central ring, 3 four-membered anti-aromatic rings become stable to from (I). In (II), due to the reduction of terminal ring, only one anti-aromatic ring can be stabilised.

Statement - I : If two sides of a triangle are 4 and 5, then its area lies in (0, 10] Because : Statement - II : Area of a triangle =1/2a b\ s in C\ a n d\ s in C\ in (0,\ 1] A (b) B (c) C (d) D

(a) Statement I is true, Statement II is true , Statement II is a correct explanation for statement I. (b) Statement I is true, Statement II is true, Statement II is not a correct explanation for Statement I. (C) Statement I is true, Statement II is false. (D) Statement I is false , Statement II is true. Statement I through the point (pi,pi+1),pilt2 , there cannot be more than one normal to the parabola y^2=4ax . Statement II The point (pi,pi+1) cannot lie inside the parabola y^2=4ax .