Statement I: `D-3` Deoxyglucose has gfour chiral `C` atoms.
Statement II: It exists in eight stereoisomers.

Options

A. Statement `I` is true, Statement `II` is true, Statements `II` is the correct explanation of Statement `I`.
B. Statement `I` is true, Statement `II` is true, Statement `II` is not the correct explanation of Statement `I`.
C. Statement `I` is true, Statement `II` is false.
D. Statement `I` is false, Statement `II` is true.

Explanation

To solve the question regarding D-3 Deoxyglucose and its chiral carbon atoms and stereoisomers, we will analyze both statements step by step.

### Step 1: Understanding Chiral Carbons
A chiral carbon atom is defined as a carbon atom that is attached to four different groups. To determine the number of chiral carbons in D-3 Deoxyglucose, we need to draw its structure.

### Step 2: Drawing the Structure of D-3 Deoxyglucose
The structure of D-3 Deoxyglucose can be represented as follows:

```
CHO
|
H - C - OH
|
H - C - H
|
H - C - OH
|
CH2OH
```

### Step 3: Identifying Chiral Carbons
Now, we will identify the chiral carbons in the structure:

1. **First Carbon (C1)**: Attached to -CHO (aldehyde), -H, -OH, and -C2. This carbon is not chiral because it has a double bond to oxygen (not four different groups).

2. **Second Carbon (C2)**: Attached to -H, -OH, -C1, and -C3. This carbon is chiral because it has four different groups attached.

3. **Third Carbon (C3)**: Attached to -H, -H, -C2, and -C4. This carbon is not chiral because it has two identical hydrogen atoms.

4. **Fourth Carbon (C4)**: Attached to -H, -OH, -C3, and -CH2OH. This carbon is chiral because it has four different groups.

5. **Fifth Carbon (C5)**: Attached to -H, -H, -C4, and -OH. This carbon is not chiral because it has two identical hydrogen atoms.

### Step 4: Counting Chiral Carbons
From the analysis above, we find that D-3 Deoxyglucose has **two chiral carbon atoms** (C2 and C4).

### Step 5: Calculating the Number of Stereoisomers
The number of stereoisomers can be calculated using the formula \(2^n\), where \(n\) is the number of chiral centers. Since we have 2 chiral centers:

\[ \text{Number of stereoisomers} = 2^2 = 4 \]

### Conclusion
- **Statement I**: D-3 Deoxyglucose has four chiral carbon atoms. **(False)**
- **Statement II**: It exists in eight stereoisomers. **(False, it exists in four stereoisomers)**

Thus, both statements are incorrect.

### Final Answer
Both Statement I and Statement II are false.

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