Complete the following reaction.

Explanation

`a.`

Ring expansion from path `(a)` is more feasible than from path `(b)` because via path `(b)` there is more steric hindrance. But product `(B)` is more stable than `(A)`.
Therefore, both the products are formed.
`b.` Mechanism with `POCI_(3)+`Pyridine `(` this method id effective because of easy formation of alkene due to good leaving group `).`

`c.`
`d.`
`e.` The `(C-H)` cleavage is about seven times stronger than the `(C-D)` cleavage, so product `(A)` is formed seven times faster than product `(B)`.
`f.`
Formatio of `(A)` is faster than `(B)`. But `(A)` is formed inmajor amount (Saytzeff's product, more `-` substituted alkene) than `(B)`.
In other words, one can conclude that the formation of `(A)` is kinetically controlled, whereas the formation fo `(B)` is thermodynamically controlled.
`g.`

Numbering in accordane with the problem Numbering in accordance with the naming of the compound
Prodct `(C)`, six`-` membered ring is mores stable than five`-` memebered ring because ring strain has been relieved `(i.e.,` from five `-` membered rind to six `-` memebered rind, the ring strain has decreased `)`. ltbr. But both `(A)` and `(B)` are equally stable and are Saytzeff's product and trisubstituted alkenes.
All the three products are possible. The stability order is `(C) gt (A)=(B)`