An alkyl halide `(X)`of the folmula `C_(6)H_(13)Cl` on treatment with potassium tertiary butoxide gives two isomeric alkenes `(Y)` and `(Z)(C_(6)H_(12))`. Both the alkenes on hydrogenation give `2,3-`dimethyl butane. Perdict the structures of `(X),(Y)` , and `(Z)`

Explanation

To solve the question, we need to determine the structures of the alkyl halide (X) and the two isomeric alkenes (Y and Z) based on the information provided. Let's break down the solution step by step.

### Step 1: Identify the Alkyl Halide (X)
The alkyl halide has the formula C₆H₁₃Cl. This indicates that it is a saturated compound with one chlorine atom. The general structure of a C₆ alkyl halide can be represented as follows:

- The carbon skeleton can be a straight chain or branched.
- Since we have a chlorine atom, we can place it on one of the carbon atoms.

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