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2-Hexyne gives cis -2- hexene on treatme...

`2-`Hexyne gives cis `-2-` hexene on treatment with `:`

A

`Li//NH_(3)`

B

`Pd//BaSO_(4)`

C

`LiAlH_(4)`

D

`Pt//H_(2)`

Text Solution

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The correct Answer is:
To solve the question regarding the conversion of 2-Hexyne to cis-2-Hexene, we need to analyze the reactions that can lead to this transformation. ### Step-by-Step Solution: 1. **Identify the Starting Material**: - The starting material is 2-Hexyne, which has the structure: \[ \text{CH}_3\text{C} \equiv \text{C}\text{CH}_2\text{CH}_3 \] - This compound is an alkyne with a triple bond between the second and third carbon atoms. 2. **Understanding the Reaction Conditions**: - To convert an alkyne to a cis-alkene, we typically need to use a specific type of catalyst. One common method is using a Lindlar catalyst, which is a poisoned palladium catalyst. 3. **Reaction with Lindlar Catalyst**: - When 2-Hexyne is treated with a Lindlar catalyst (Pd/BaSO4), it undergoes partial hydrogenation. This process selectively reduces the triple bond to a double bond while maintaining the cis configuration. - The reaction can be represented as: \[ \text{CH}_3\text{C} \equiv \text{C}\text{CH}_2\text{CH}_3 \xrightarrow{\text{H}_2, \text{Lindlar}} \text{cis-2-Hexene} \] 4. **Product Formation**: - The product of this reaction is cis-2-Hexene, which has the structure: \[ \text{CH}_3\text{CH}=\text{CH}\text{CH}_2\text{CH}_3 \] - In this structure, the two substituents (the two CH3 groups) are on the same side of the double bond, confirming the cis configuration. 5. **Conclusion**: - Therefore, the treatment of 2-Hexyne with a Lindlar catalyst results in the formation of cis-2-Hexene. ### Final Answer: 2-Hexyne gives cis-2-Hexene on treatment with Lindlar catalyst (Pd/BaSO4). ---

To solve the question regarding the conversion of 2-Hexyne to cis-2-Hexene, we need to analyze the reactions that can lead to this transformation. ### Step-by-Step Solution: 1. **Identify the Starting Material**: - The starting material is 2-Hexyne, which has the structure: \[ \text{CH}_3\text{C} \equiv \text{C}\text{CH}_2\text{CH}_3 ...
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