`CH_(3)CH=CH_(2)+NOClrarrP`
Identify the product.

Options

A. `CH_(3)-underset(Cl)underset(|)(CH)-underset(NO)underset(|)CH_(2)`
B. `CH_(3)-underset(NO)underset(|)(CH)-underset(Cl)underset(|)CH_(2)`
C. `CH_(3)-CH_(2)-underset(Cl)underset(|)(CH)-NO`
D. `underset(NO)underset(|)(NO_(2))-CH_(2)-underset(Cl)underset(|)(CH)`

Explanation

To identify the product of the reaction between propene (CH₃CH=CH₂) and NOCl, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are propene (CH₃CH=CH₂) and NOCl.

### Step 2: Understand the Mechanism
NOCl dissociates into NO⁺ (electrophile) and Cl⁻ (nucleophile). In electrophilic addition reactions, the electrophile attacks the double bond of the alkene.

### Step 3: Electrophilic Attack
The double bond in propene will react with the NO⁺. The π bond (double bond) will break, and one of the carbon atoms will form a carbocation. In this case, the more stable secondary carbocation will form on the second carbon (C2) of propene.

### Step 4: Formation of the Carbocation
The carbocation formed will be:
- CH₃-CH⁺-CH₂-NO
This carbocation is stable because it is a secondary carbocation.

### Step 5: Nucleophilic Attack
Now, the Cl⁻ ion will attack the positively charged carbon (C2) of the carbocation. The chloride ion will bond with this carbon.

### Step 6: Product Formation
The final product after the nucleophilic attack will be:
- CH₃-CH(Cl)-CH₂-NO
This can be written as CH₃-CHCl-CH₂-NO.

### Conclusion
The product P formed from the reaction of propene with NOCl is CH₃CHClCH₂NO.