The reagents `(A), (B)`, and `(C )` are:

Options

A. a.
B. b.
C. c.
D. d.

Answer

D

Explanation

`(H_(2)+Pt)`can reduce both `(C=C)` bond and `(C=O)` group, but `(C=C)` is more reactive than `(C=O)` towards the reduction, so with `1 mol` of `(H_(2)+Pt)`, only `(C=C)` bond is reduced to `(C-C)` bond. While `(H_(2)+Pt)` or `(H_(2)+ "Raney" Ni)` in excess reduce both `(C=C)` bond to `(C-C)` bond and

group to

group, `NaBH_(4)` reduces only

group to

group, but does not reduce `(C=C)` bond. So the answer is `(d)`.