An aromatic compound `(A), C_(8)H_(10)`, on oxidation with acidic `KMnO_(4)` gives dibasic acid. The compound `(A)` on nitration gives three isomeric nitro derivatives. The compound (A) is:

Options

A. a.o-Xylene
B. b.m-Xylene
C. c.p-Xylene
D. d.Ethyl benzene

Explanation

To solve the question about the aromatic compound (A), C₈H₁₀, we will follow these steps:

### Step 1: Identify the structure of compound (A)
Since compound (A) is an aromatic compound with the molecular formula C₈H₁₀, it must contain a benzene ring. The presence of two additional carbons (from the formula) suggests that there are two methyl groups attached to the benzene ring. The possible structures for C₈H₁₀ can be:
- Ortho-xylene (1,2-dimethylbenzene)
- Meta-xylene (1,3-dimethylbenzene)
- Para-xylene (1,4-dimethylbenzene)

### Step 2: Analyze the oxidation reaction
The question states that upon oxidation with acidic KMnO₄, compound (A) gives a dibasic acid.
- Ortho-xylene and para-xylene would yield monobasic acids (benzoic acid) upon oxidation.
- Meta-xylene, however, can be oxidized to isophthalic acid, which is a dibasic acid.

### Step 3: Analyze the nitration reaction
The compound (A) also gives three isomeric nitro derivatives upon nitration.
- Ortho-xylene would yield two isomers (ortho and para).
- Para-xylene would yield only one isomer (para).
- Meta-xylene would yield three isomers (one meta and two ortho).

### Step 4: Conclusion
Since meta-xylene (1,3-dimethylbenzene) can be oxidized to isophthalic acid (a dibasic acid) and can produce three isomeric nitro derivatives upon nitration, we conclude that the compound (A) is **meta-xylene**.

### Final Answer
The compound (A) is **meta-xylene** (1,3-dimethylbenzene).

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