`PhCH_(2)CH_(2)CH_(3) underset((ii) h_(2)O)overset((i) CrO_(2)Cl_(2)//C Cl_(4))(rarr) (A)`
The product `(A)` is:

Options

A. a.`PhCHO`
B. b.`PhCH_(2)CHO`
C. c.`PhCH_(2)CH_(2)CHO`
D. d.`Phoverset(CH_(3))overset(|)(PhCH)-CHO`

Explanation

To solve the given question, we need to analyze the reaction involving the compound \( \text{PhCH}_2\text{CH}_2\text{CH}_3 \) with the reagents \( \text{CrO}_2\text{Cl}_2 \) in the presence of \( \text{CCl}_4 \) and \( \text{H}_2\text{O} \). This reaction is known as the Etard reaction, which is used to convert terminal alkyl groups into aldehydes.

### Step-by-Step Solution:

1. **Identify the Structure of the Compound**:
The compound \( \text{PhCH}_2\text{CH}_2\text{CH}_3 \) can be represented as:
\[ \text{Ph} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \]
Here, "Ph" represents the phenyl group (C6H5).

2. **Understand the Reagents**:
The reagent \( \text{CrO}_2\text{Cl}_2 \) in the presence of \( \text{CCl}_4 \) is used to perform the Etard reaction. This reagent will oxidize the terminal methyl group (–CH3) of the alkyl chain to an aldehyde.

3. **Formation of the Intermediate**:
During the Etard reaction, the chromium complex is formed. The intermediate can be represented as:
\[ \text{Ph} - \text{CH}_2 - \text{CH}_2 - \text{C(OCrCl)_2} \]
This intermediate contains a chromium atom bonded to the carbon that was initially part of the terminal methyl group.

4. **Hydrolysis of the Intermediate**:
The presence of water \( \text{H}_2\text{O} \) leads to hydrolysis of the chromium complex. The chromium complex will facilitate the removal of the chromium and the formation of an aldehyde. The terminal carbon will be oxidized to form an aldehyde group (–CHO).

5. **Final Product Formation**:
After hydrolysis, the final product will be:
\[ \text{Ph} - \text{CH}_2 - \text{CH}_2 - \text{CHO} \]
This compound is known as phenylpropanal.

6. **Identify the Correct Option**:
Based on the structure of the final product, the correct answer is option C, which corresponds to phenylpropanal.

### Final Answer:
The product \( (A) \) is phenylpropanal.