The oxidation product of `1,2`-cyclopentane diol with `HIO_(4)` or `(CH_(3)COO)_(4) Pb` is:

Options

A. a.
B. b.
C. c.
D. d. None

Explanation

To solve the question regarding the oxidation product of 1,2-cyclopentane diol with HIO₄ or (CH₃COO)₄Pb, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactant:**
The reactant is 1,2-cyclopentane diol, which has two hydroxyl (-OH) groups attached to the first and second carbon atoms of a cyclopentane ring.

2. **Understand the Oxidizing Agents:**
The oxidizing agents mentioned are periodic acid (HIO₄) and lead tetraacetate [(CH₃COO)₄Pb]. Both of these reagents are known to cleave vicinal diols (diols with hydroxyl groups on adjacent carbons) and convert them into carbonyl compounds.

3. **Reaction Mechanism:**
- When 1,2-cyclopentane diol reacts with periodic acid, the hydroxyl groups (-OH) will react with the oxidizing agent.
- The reaction leads to the formation of a cyclic intermediate where the -OH groups are replaced by two carbonyl (C=O) groups.
- Specifically, the -OH groups are oxidized, and water is eliminated, resulting in the formation of carbonyl groups.

4. **Formation of Carbonyl Compounds:**
- The cleavage of the C-O bonds occurs, leading to the formation of two carbonyl groups (C=O) at the 1 and 2 positions of the cyclopentane ring.
- This results in the formation of a diketone, specifically 1,2-cyclopentanedione.

5. **Final Product:**
The final product of the oxidation of 1,2-cyclopentane diol with HIO₄ or (CH₃COO)₄Pb is **1,2-cyclopentanedione**.

### Conclusion:
Thus, the oxidation product of 1,2-cyclopentane diol with HIO₄ or (CH₃COO)₄Pb is **1,2-cyclopentanedione**.