`C_(2)H_(5)O-overset(O)overset(||)(C )-OC_(2)H_(5) overset(2MeMgBr)(rarr) (A)`. The product `(A)` formed can:

Options

A. a.give iodoform test.
B. b.further react with `MeMgBr//H_(3)O^(o+)` to give t-butyl alcohol.
C. c.be obtained by the ozonolysis of 2, 3-dimethyl 1-2-butene.
D. d.all correct

Explanation

To solve the given problem, we will analyze the reaction step by step, focusing on the interaction between the reactants and the Grignard reagent.

### Step-by-Step Solution

1. **Identify the Reactants**: The starting compound is an ether with the structure C2H5O-C(=O)-C2H5, which contains a carbonyl group (C=O) and two ethyl groups (C2H5).

2. **Reaction with Grignard Reagent**: The compound reacts with two moles of methyl magnesium bromide (MeMgBr). The carbonyl group is electrophilic and will react with the nucleophilic methyl group from the Grignard reagent.

3. **First Reaction Step**:
- The methyl group (CH3-) from the first mole of MeMgBr attacks the carbonyl carbon (C=O), forming an alkoxide intermediate.
- The oxygen atom in the carbonyl group becomes negatively charged, while the carbon becomes positively charged.
- The reaction can be represented as:
\[ C2H5O-C(=O)-C2H5 + CH3MgBr \rightarrow C2H5O-C(-O^{-}CH3)-C2H5 \]

4. **Formation of the Intermediate**: The intermediate formed after the first reaction is a tetrahedral alkoxide. The negatively charged oxygen will now have a bond with the methyl group.

5. **Leaving Group**: The alkoxide intermediate can then collapse, leading to the elimination of the ethoxy group (C2H5O-) as a good leaving group. This results in the formation of a ketone:
\[ C2H5O-C(-O)-C2H5 \rightarrow C2H5-C(=O)-CH3 + C2H5O^{-} \]
This ketone is acetone (CH3COC2H5).

6. **Second Reaction Step**: The second mole of MeMgBr will now attack the carbonyl carbon of the formed acetone:
\[ CH3COC2H5 + CH3MgBr \rightarrow CH3C(OH)(C2H5)CH3 \]
This results in the formation of a tertiary alcohol after hydrolysis.

7. **Final Product**: The final product after hydrolysis is a tertiary butyl alcohol (tert-butanol).

8. **Tests for Product A**: The product formed, acetone, can undergo the iodoform test, which is characteristic of methyl ketones. Additionally, ozonolysis of 2,3-dimethylbutene can yield acetone.

### Conclusion
The final product (A) formed from the reaction can give the iodoform test and can also be prepared from the ozonolysis of 2,3-dimethylbutene.