Fenton's regent `(Fe^(2+)+H_(2)O_(2))` with benzene gives:

Options

A. a.`No reaction`
B. b.
C. c.
D. d.`3(HOOC-COOH)`

Explanation

To solve the question regarding the reaction of Fenton's reagent `(Fe^(2+) + H_(2)O_(2))` with benzene, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are benzene `(C6H6)`, Fenton's reagent which consists of ferrous ions `(Fe^(2+))` and hydrogen peroxide `(H2O2)`.

2. **Write the Reaction**:
- The reaction can be represented as:
\[ C6H6 + Fe^{2+} + H2O2 \rightarrow ? \]

3. **Understand the Role of Fenton's Reagent**:
- Fenton's reagent is known for its ability to oxidize organic compounds. In this case, it will oxidize benzene.

4. **Predict the Product**:
- The oxidation of benzene by Fenton's reagent typically leads to the formation of phenol `(C6H5OH)`. The reaction involves the addition of a hydroxyl group to the benzene ring.

5. **Write the Balanced Equation**:
- The balanced equation for the reaction can be written as:
\[ C6H6 + H2O2 \xrightarrow{Fe^{2+}} C6H5OH + H2O \]
- This indicates that benzene is converted to phenol, along with the production of water.

6. **Conclusion**:
- The product formed when benzene reacts with Fenton's reagent is phenol `(C6H5OH)`.

### Final Answer:
The product formed when Fenton's reagent `(Fe^(2+) + H_(2)O_(2))` reacts with benzene is **phenol `(C6H5OH)`**.