Compound (X) with molecular formula `C_(3)H_(8)O` is treated with acidified potassium dichromate to form a product (Y) with molecular formula `C_(3)H_(6)O`. (Y) does not form a shining silver mirror on warming with ammoniacal `AgNO_(3)`. (Y) when treated with an aqueous solution of `NH_(2)CONHNH_(2).HCl` and sodium acetate, gives a product (Z). The structure of (Z) is

Options

A. a.`CH_(3)CH_(2)CH=N.NHCONH_(2)`
B. b.`CH_(3)-underset(CH_(3))underset(|)(CH_(3))=N.NHCONH_(2)`
C. c.`CH_(3)-underset(CH_(3))underset(|)(CH_(3))=N.CONHNH_(2)`
D. d.`CH_(2)CH_(2)CH=N.CONHNH_(2)`

Answer

A

Explanation

`DU` in `A =((2n_(C )+2)-n_(H))/2=((2xx3+2)-8)/2=0`
So, compound A is `1^(@)` alcohol.

Hence the answer the answer is `(a)`.