Among the following in which cases is the `o//p` ratio on nitration more the first compound?

Explanation

(c,d)
In (a) and (c) in the nitration of `alkyl` benzene, the `o//p` ratio is the order `Me (1.58) gt Et (0.94) gt Me_(2)CH-(0.49) gt Me_(2)C (0.22)`. This is largly due to the steric effect of the alkyl group and `overline(e)` donation by hyperconjugation.
So, the reactivity order is: `PhCH_(3) gt PhEt gt PhCHMe_(2) gt PhCMe_(3)`.
So, in (b) adn `o//p` ratio is: `(II) gt (i)`. In (c), the `o//p` ratio is: `(I) gt (II)`.
So, in (b) and (d), for nitraction of halogen substituent, the reactivity oder is: `I gt Br gt Cl gt F` (due to combined effect of `-1` and `+R`).
So, in (b), `o/p` ratio is: `(II) gt (I)`
So in `(d), o//p` ratio is (I) gt (II)`