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The decreasing nucleophilic order of the...

The decreasing nucleophilic order of the following compounds is:
i. `NH_(3)`, ii. `PH_(3)`, iii. `AsH_(3)`, iv. `SbH_(3)`

A

`(i) gt (ii) gt (iii) gt (iv)`

B

`(iv) gt (iii) gt (ii) gt (i)`

C

`(ii) gt (i) gt (iii) gt (iv)`

D

`(ii) gt (i) gt (iv) gt (iii)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the decreasing nucleophilic order of the compounds NH₃, PH₃, AsH₃, and SbH₃, we need to analyze the nature of these compounds as nucleophiles, which are species that donate electron pairs. Here’s a step-by-step breakdown of the reasoning: ### Step 1: Identify the Compounds The compounds given are: 1. NH₃ (Ammonia) 2. PH₃ (Phosphine) 3. AsH₃ (Arsine) 4. SbH₃ (Stibine) ### Step 2: Understand Nucleophilicity Nucleophilicity is influenced by the ability of an atom to donate its lone pair of electrons. The central atom's size and electronegativity play crucial roles in determining this ability. ### Step 3: Analyze the Group Trend These compounds belong to Group 15 of the periodic table. As we move down the group from nitrogen to antimony: - The size of the central atom increases (N < P < As < Sb). - The electronegativity decreases (N > P > As > Sb). ### Step 4: Basicity vs. Nucleophilicity - Basicity refers to the ability to accept protons (H⁺), which is generally stronger for smaller atoms with higher electronegativity. - Nucleophilicity, however, is the ability to donate electrons, which increases with larger atomic size in the same group, as the lone pair becomes more available for donation. ### Step 5: Determine the Nucleophilic Order Based on the above analysis: - NH₃ is the least nucleophilic because it is the smallest and most electronegative, making it a stronger base but a weaker nucleophile. - PH₃ is slightly more nucleophilic than NH₃ due to its larger size. - AsH₃ is more nucleophilic than PH₃. - SbH₃ is the most nucleophilic due to its larger size and lower electronegativity, allowing for easier donation of the lone pair. ### Conclusion Thus, the decreasing order of nucleophilicity is: **SbH₃ > AsH₃ > PH₃ > NH₃** ### Final Answer The correct order is **SbH₃ > AsH₃ > PH₃ > NH₃**. ---

To determine the decreasing nucleophilic order of the compounds NH₃, PH₃, AsH₃, and SbH₃, we need to analyze the nature of these compounds as nucleophiles, which are species that donate electron pairs. Here’s a step-by-step breakdown of the reasoning: ### Step 1: Identify the Compounds The compounds given are: 1. NH₃ (Ammonia) 2. PH₃ (Phosphine) 3. AsH₃ (Arsine) 4. SbH₃ (Stibine) ...
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The decreasing basic order of the following compounds is: i. NH_(3) , ii. PH_(3) , iii. AsH_(3) , iv. SbH_(3)

The decreasing nucleophillic order fo the following compounds is: i. F^(o-) , ii. Cl^(o-) , iii. Br^(o-) , Iv. I^(o-)

The decreasing nucleophilic order of the following compounds is: i. PhSO_(3)^(o-) , ii. C_(2)H_(5)SO_(3)^(o-) , iii. C_(2)H_(5)COO^(o-) , iv. overset(o-)(C)N , v. overset(o-)(O)H

The decreasing nucelophilic order of the following compounds is: i. overset(o-)(C)H_(3) , ii. overset(o-)(O)H , iii. CH_(3)COO^(o-) , iv. H_(2)O

The decreasing nucleophilic oder of the following compounds is: i. overset(o-)(C)H_(3) , ii. overset(o-)(N)H_(2) , iii. overset(o-)(O)H , iv. F^(o-)

Decreasing nucelophilic order of the following is: i. Me_(2)N - Nme_(2) , ii. MeNH-NHMe iii. H_(2)N - NH_(2) , iv. NH_(3)

The decreasing leaving group order of the following is: i. F_(3)CSO_(3)^(o-) , ii. Cl_(3)C-COO^(o-) iii. PhSO_(3)^(o-) , iv. MeSO_(3)^(o-)

The decresing fugacity order of the following is: i. Me_(2)N - Nme_(2) , ii. MeNH-NHMe iii. H_(2)N - NH_(2) , iv. NH_(3)

Arrange the following in the increasing order of the properties stated against them. (a) (i) NH_(3) , (ii) PH_(3) , (iii) AsH_(3) , (iv) SbH_(3) -boiling point. (b)(i) Bi^(3+) ,(ii) Sb^(3+) , (iii) As^(3+) -stability of +3 oxidation state. ( c)(i) NH_(3) , (ii) PH_(3) , (iii) AsH_(3) , (iv) SbH_(3) , (v) BiH_(3) -reducing character.

The decreasing order of acidic character of the following is: (I) (II) (III) (IV)

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