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Alkyl halides can be obtained by all met...

Alkyl halides can be obtained by all methods except

A

`CH_(3)CH_(2)OH + HX//ZnCl_(2)`

B

`CH_(2) = CH - CH_(3) underset(475K)overset(SO_(2) Cl_(2)(rarr)`

C

`C_(2)H_(5) OH + NaCl`

D

`CH_(3)COOAg + Br_(2)//C Cl_(4)`

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To solve the question "Alkyl halides can be obtained by all methods except," we need to evaluate the different methods mentioned and determine which one does not yield alkyl halides. ### Step-by-Step Solution: 1. **Identify the Methods**: We need to analyze the methods provided in the question. The methods typically include: - Reaction of alcohol with hydrogen halides. - Halogenation of alkenes. - Reaction of alcohol with salts. - Reaction involving silver carboxylic salts. 2. **First Method - Alcohol with Hydrogen Halides**: - When ethanol reacts with hydrogen halides (like HCl), it produces alkyl halides. For example, ethanol reacts with HCl to form ethyl chloride and water. - **Conclusion**: This method can produce alkyl halides. 3. **Second Method - Alkene with Thionyl Chloride**: - An alkene (like propene) reacts with thionyl chloride (SOCl2) to undergo halogenation, resulting in the formation of alkyl halides. - **Conclusion**: This method can also produce alkyl halides. 4. **Third Method - Alcohol with Sodium Chloride**: - When ethanol reacts with sodium chloride (NaCl), no reaction occurs. The chloride ions from NaCl are not strong enough to break the carbon-oxygen bond in ethanol. - **Conclusion**: This method does NOT produce alkyl halides. 5. **Fourth Method - Silver Carboxylic Salt with Bromine**: - In Hund's Dicker reaction, a silver carboxylic salt reacts with bromine in a non-polar medium (like CCl4) to produce alkyl halides along with carbon dioxide and silver bromide. - **Conclusion**: This method can produce alkyl halides. 6. **Final Conclusion**: - The only method that does not yield alkyl halides is the reaction of ethanol with sodium chloride. Therefore, the answer to the question is option **C**. ### Summary of the Answer: Alkyl halides can be obtained by all methods except the reaction of ethanol with sodium chloride (option C).

To solve the question "Alkyl halides can be obtained by all methods except," we need to evaluate the different methods mentioned and determine which one does not yield alkyl halides. ### Step-by-Step Solution: 1. **Identify the Methods**: We need to analyze the methods provided in the question. The methods typically include: - Reaction of alcohol with hydrogen halides. - Halogenation of alkenes. - Reaction of alcohol with salts. ...
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CENGAGE CHEMISTRY ENGLISH-AROMATIC COMPOUNDS AND ALKYL AND ARYL HALIDES -Exercises Single Correct
  1. underset("Specific rotation" = +50^(@))(Ph-CH(OH)CH(3)) overset(SOCl(2...

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  2. CH(3) - CH(Cl) - C(2)H(5) overset(Alc.KOH)(rarr) CH(3) - CH = CH - CH(...

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  3. Alkyl halides can be obtained by all methods except

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  4. Neopentyl chloride on reaction with ethanolic KOH is likely to give

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  5. In the reaction CH(3)C equiv C^(-)Na^(+) + (CH(3))(2) CHCl rarr Prod...

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  6. In order to get ethanethiol from bromoethane, the reagent used is :

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  7. For the preparation of chloroethane,

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  8. X on treatment with sodium hydroxide followed by the addition of silve...

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  9. Which of the following cannot be used for the preaparation of iodofro...

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  10. Which of the following hladies is capable of exhibitin enantiomerism?

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  11. A suspension of CaOCl(2) in water is heated with ethanol, the product ...

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  12. Pick up the correct statements about alkyl halides.

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  13. Which of the following is a geminal dihalide ?

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  14. C(2)H(5)I overset(AgNO(2))rarr underset(("major product"))("X. Here X"...

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  15. Which of the following sequence would yield m-nitrochlorobenzene (Z) f...

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  16. C(3)H(7) Cl overset(KOH(alc.))(rarr) (A) underset(770K)overset(Cl(2) (...

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  17. Which of the following alkyl halides undergoes the fastest S(N^(1)) re...

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  18. Choose the incorrect reaction.

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  19. In order to convert aniline into chlorobenzene the reagents needed are

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  20. The reaction between chloral and chlorobenzene in H(2)SO(4) yields:

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