Neopentyl chloride on reaction with ethanolic KOH is likely to give

Options

A. Neopentyl alcohol
B. Pentylene
C. `2-` Mentyl `-2` butene
D. Undergo no reaction

Explanation

To solve the question regarding the reaction of neopentyl chloride with ethanolic KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**:
Neopentyl chloride is a five-carbon alkyl halide with the structure:
\[ \text{(CH}_3\text{)}_4\text{CCl} \]
This structure indicates that neopentyl chloride has a central carbon atom bonded to four methyl groups and one chlorine atom.

2. **Understand the Reaction Conditions**:
The reaction involves ethanolic KOH, which is a strong base. When alkyl halides react with alcoholic KOH, they typically undergo elimination reactions to form alkenes.

3. **Determine the Type of Reaction**:
The elimination reaction requires the presence of an alpha hydrogen atom (hydrogens attached to the carbon adjacent to the carbon bearing the halide). This is because the elimination process involves the removal of a halide (Cl in this case) and a hydrogen atom from adjacent carbons.

4. **Analyze the Structure of Neopentyl Chloride**:
In the case of neopentyl chloride, the central carbon (the one attached to Cl) does not have any alpha hydrogen atoms. The four methyl groups are attached to this carbon, and there are no hydrogens available on the adjacent carbon atoms that could be removed.

5. **Conclusion**:
Since neopentyl chloride lacks alpha hydrogen atoms, it cannot undergo an elimination reaction with ethanolic KOH. Therefore, no reaction will occur.

### Final Answer:
Neopentyl chloride on reaction with ethanolic KOH is likely to give **no reaction**.

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