X on treatment with sodium hydroxide followed by the addition of silver nitrate give white precipitate at room temperature which are soluble in `NH_(4)OH`. X can be :

Options

A. Chlorbenzene
B. Ethyl bromide
C. Benzyl chloride
D. Vinyl chloride

Explanation

To solve the problem, we need to identify the compound X based on the given reactions and observations. Let's break it down step by step.

### Step 1: Understand the Reaction
The problem states that compound X, when treated with sodium hydroxide (NaOH) and then silver nitrate (AgNO3), produces a white precipitate at room temperature. The white precipitate is soluble in ammonium hydroxide (NH4OH).

### Step 2: Identify the White Precipitate
The white precipitate formed when silver nitrate is added to a solution containing chloride ions (Cl-) is silver chloride (AgCl). Therefore, we can conclude that compound X must be capable of releasing chloride ions when treated with NaOH.

### Step 3: Analyze Possible Compounds
Now, let's analyze the potential candidates for compound X:
1. **Chlorobenzene (C6H5Cl)**:
- Chlorobenzene does not react with NaOH to release Cl- due to the partial double bond character of the C-Cl bond. Therefore, it cannot produce AgCl.

2. **Ethyl Bromide (C2H5Br)**:
- Ethyl bromide would release bromide ions (Br-) upon treatment with NaOH, leading to the formation of AgBr, which is a yellow precipitate. Thus, it cannot be the answer since we need a white precipitate.

3. **Benzyl Chloride (C6H5CH2Cl)**:
- Benzyl chloride has a benzylic carbon, and when treated with NaOH, it can release chloride ions (Cl-). This would lead to the formation of AgCl, which is a white precipitate. Additionally, AgCl is soluble in ammonium hydroxide.

4. **Vinyl Chloride (C2H3Cl)**:
- Vinyl chloride also has a C-Cl bond with partial double bond character, making it unreactive towards NaOH. Thus, it cannot produce AgCl.

### Step 4: Conclusion
Based on the analysis, the only compound that fits all the criteria is **Benzyl Chloride (C6H5CH2Cl)**. It can release chloride ions when treated with NaOH, leading to the formation of a white precipitate of AgCl, which is soluble in ammonium hydroxide.

### Final Answer
The compound X can be: **Benzyl Chloride (C6H5CH2Cl)**.

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