A suspension of `CaOCl_(2)` in water is heated with ethanol, the product formed is :

Options

A. Ethyene
B. Ethanol
C. Trichloromethane
D. Chloroenthane

Explanation

To solve the question regarding the reaction of a suspension of `CaOCl2` (calcium oxychloride) in water with ethanol, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
We have calcium oxychloride (`CaOCl2`) and ethanol (`C2H5OH`) as the reactants.

2. **Reaction of Calcium Oxychloride with Water**:
When `CaOCl2` is added to water, it dissociates to form calcium hydroxide and chlorine gas:
\[ CaOCl2 + H2O \rightarrow Ca(OH)2 + Cl2 \]

3. **Formation of Nascent Oxygen**:
The chlorine gas produced can further react with water to generate nascent oxygen:
\[ Cl2 + H2O \rightarrow HCl + [O] \]
Here, nascent oxygen (`[O]`) is a reactive form of oxygen.

4. **Oxidation of Ethanol**:
The nascent oxygen will oxidize ethanol to form acetaldehyde:
\[ C2H5OH + [O] \rightarrow CH3CHO + H2O \]

5. **Reaction of Acetaldehyde with Chlorine**:
Acetaldehyde can further react with chlorine. In this case, it reacts with three moles of chlorine:
\[ CH3CHO + 3Cl2 \rightarrow CCl3CHO + 3HCl \]
Here, the product formed is trichloroacetaldehyde.

6. **Formation of Chloroform**:
The trichloroacetaldehyde can then react with calcium hydroxide to produce chloroform:
\[ CCl3CHO + Ca(OH)2 \rightarrow CHCl3 + CaCl2 + H2O \]
Here, chloroform (`CHCl3`) is the final product along with calcium chloride and water.

7. **Conclusion**:
The final product formed when a suspension of `CaOCl2` in water is heated with ethanol is trichloromethane (chloroform).

### Final Answer:
The product formed is **trichloromethane (chloroform)**, which corresponds to option C.