In order to convert aniline into chlorobenzene the reagents needed are

Options

A. `CuCl`
B. `NaNO_(2)//HCl` and `CuCl`
C. `Cl_(2)//C Cl_(4)`
D. `Cl_(2)//AlCl_(3)`

Explanation

To convert aniline (C6H5NH2) into chlorobenzene (C6H5Cl), we need to follow a two-step reaction process. Here’s a step-by-step solution:

### Step 1: Diazotization of Aniline
1. **Reagents Required:**
- Sodium nitrite (NaNO2)
- Hydrochloric acid (HCl)

2. **Reaction:**
- Aniline reacts with nitrous acid (which is generated in situ from NaNO2 and HCl) to form benzenediazonium chloride (C6H5N2Cl).
- The reaction can be represented as:
\[ C6H5NH2 + NaNO2 + HCl \rightarrow C6H5N2Cl + NaCl + 2H2O \]

### Step 2: Formation of Chlorobenzene
1. **Reagents Required:**
- Copper(I) chloride (CuCl)
- Hydrochloric acid (HCl)

2. **Reaction:**
- The benzenediazonium chloride then reacts with CuCl in the presence of HCl to replace the diazonium group with a chlorine atom, resulting in the formation of chlorobenzene.
- The reaction can be represented as:
\[ C6H5N2Cl + CuCl \rightarrow C6H5Cl + N2 + CuCl2 \]

### Final Product:
- The final product of this reaction sequence is chlorobenzene (C6H5Cl).

### Summary of Reagents Needed:
- **Step 1:** NaNO2 and HCl for diazotization.
- **Step 2:** CuCl and HCl for the Sandmeyer reaction.

### Conclusion:
The reagents needed to convert aniline into chlorobenzene are sodium nitrite (NaNO2), hydrochloric acid (HCl), and copper(I) chloride (CuCl).

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