The reaction between chloral and chlorobenzene in `H_(2)SO_(4)` yields:

Options

A. Chloretone
B. `p,p-` Dichlorodiphenyl trichloroenthane
C. `o-` Chlorobenzaldichloride
D. Chloralphenylchloride

Explanation

To solve the question regarding the reaction between chloral and chlorobenzene in sulfuric acid (H₂SO₄), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Chloral (CCl₃CHO) is an aldehyde with three chlorine atoms attached to the carbon.
- Chlorobenzene (C₆H₅Cl) is a benzene ring with one chlorine atom attached.

2. **Understand the Reaction Medium**:
- The reaction takes place in the presence of sulfuric acid (H₂SO₄), which acts as a catalyst and provides an acidic medium.

3. **Mechanism of Reaction**:
- In the acidic medium, chloral can form a carbocation. The chlorine atoms in chlorobenzene can act as nucleophiles.
- The reaction involves the electrophilic substitution of the chlorobenzene by the chloral.

4. **Formation of the Product**:
- The chloral reacts with chlorobenzene to form a complex compound. The reaction leads to the formation of a compound known as para-dichlorodiphenyltrichloroethane (DDT).
- This occurs through the removal of water (dehydration) and the formation of new carbon-carbon bonds.

5. **Final Product**:
- The final product of the reaction is para-dichlorodiphenyltrichloroethane (DDT), which is represented as C₁₄H₉Cl₅.

### Conclusion:
The reaction between chloral and chlorobenzene in H₂SO₄ yields para-dichlorodiphenyltrichloroethane (DDT).