Iodofrom can be prepared from:

Options

A. Isoamyl alcohol
B. `alpha-` Phenyl ethanol
C. Isobutyl alcohol
D. `beta-`Phenyl ethanol

Explanation

To determine which compound can prepare Iodoform, we need to analyze the given alcohols based on the presence of the required structural feature. Iodoform can be formed from alcohols that have a methyl group (CH3) adjacent to the carbon bearing the hydroxyl group (OH).

### Step-by-Step Solution:

1. **Identify the Required Structure**:
- Iodoform can be prepared from alcohols that have the structure CH3-CHOH- (where CH3 is adjacent to the carbon with the OH group).

2. **Analyze Each Compound**:
- **Compound 1: Isoamyl Alcohol**
- Structure: CH3-CH2-CH(CH3)-CH2OH
- Analysis: There is no methyl group adjacent to the OH group. Therefore, it cannot form Iodoform.

- **Compound 2: Alpha Phenyl Ethanol**
- Structure: C6H5-CH(OH)-CH3
- Analysis: There is a methyl group adjacent to the OH group. Therefore, it can form Iodoform.

- **Compound 3: Isobutyl Alcohol**
- Structure: (CH3)2CH-CH2OH
- Analysis: There is no methyl group adjacent to the OH group. Therefore, it cannot form Iodoform.

- **Compound 4: Beta Phenyl Ethanol**
- Structure: C6H5-CH2-CH(OH)-CH3
- Analysis: The methyl group is not adjacent to the OH group (it is on the beta carbon). Therefore, it cannot form Iodoform.

3. **Conclusion**:
- The only compound that can form Iodoform is **Alpha Phenyl Ethanol** (Option B).

### Final Answer:
The compound from which Iodoform can be prepared is **Alpha Phenyl Ethanol (Option B)**.