Isopropyl alcohol is heated with a suspension of bleaching powder `(CaOCl_(2))` with water. The products are :

Options

A. Etane and propane
B. Etyne and ethene
C. Trichloromethane and sodium accetate
D. Carbon tetrachloride

Explanation

To solve the problem of what products are formed when isopropyl alcohol is heated with a suspension of bleaching powder (CaOCl₂) in water, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are isopropyl alcohol (C₃H₈O) and bleaching powder (CaOCl₂) in the presence of water.

2. **Reaction of Bleaching Powder with Water**:
- When bleaching powder (CaOCl₂) reacts with water, it produces chlorine gas (Cl₂) and calcium hydroxide (Ca(OH)₂):
\[ \text{CaOCl}_2 + \text{H}_2\text{O} \rightarrow \text{Cl}_2 + \text{Ca(OH)}_2 \]

3. **Oxidation of Isopropyl Alcohol**:
- The chlorine gas (Cl₂) generated can oxidize isopropyl alcohol. The oxidation of isopropyl alcohol leads to the formation of acetone (C₃H₆O) and hydrochloric acid (HCl):
\[ \text{C}_3\text{H}_8\text{O} + \text{Cl}_2 \rightarrow \text{C}_3\text{H}_6\text{O} + \text{HCl} \]

4. **Formation of Chloroform**:
- The acetone (C₃H₆O) can further react with chlorine in the presence of calcium hydroxide. This reaction can lead to the formation of chloroform (CHCl₃) and sodium acetate (or calcium acetate depending on the context):
\[ \text{C}_3\text{H}_6\text{O} + \text{Cl}_2 \rightarrow \text{CHCl}_3 + \text{Ca(CH}_3\text{COO)}_2 \]

5. **Final Products**:
- The final products of the reaction are chloroform (CHCl₃) and calcium acetate (Ca(CH₃COO)₂).

### Conclusion:
The products formed when isopropyl alcohol is heated with a suspension of bleaching powder and water are chloroform (CHCl₃) and calcium acetate (Ca(CH₃COO)₂).