Identify C in the following series `C_(3) H_(7)Iunderset(Alc)overset(KOH)toAunderset(Delta)overset(NBS)toBunderset(Alc)overset(KCN)toC.`

Options

A. `(CH_(3))_(2) CH-CN`
B. `CH_(2) = CH - CH_(2) CN`
C. `Br-CH=CH-CN`
D. `CH_(2) = CH - underset(Br)underset(|)(C)HCN`

Explanation

To identify compound C in the given reaction series, we will analyze each step in the reaction sequence.

### Step 1: Identify the starting compound
The starting compound is **iodopropane (C₃H₇I)**. The structure can be represented as:
```
CH3
|
CH
|
CH2I
```

### Step 2: Reaction with alcoholic KOH
When iodopropane reacts with alcoholic KOH, an elimination reaction occurs. The KOH removes the iodine and a hydrogen atom, leading to the formation of a double bond. This results in the formation of **propene (C₃H₆)**:
```
CH3
|
CH
|
CH2
```
The byproduct of this reaction is HI.

### Step 3: Reaction with N-bromosuccinimide (NBS)
Next, propene undergoes bromination at the allylic position when treated with N-bromosuccinimide (NBS). The allylic carbon is the one adjacent to the double bond. The bromine radical will add to the allylic carbon, resulting in the formation of **allyl bromide (C₃H₅Br)**:
```
CH2Br
|
CH
|
CH2
```
The byproduct of this reaction is succinimide.

### Step 4: Reaction with alcoholic KCN
Finally, the allyl bromide reacts with alcoholic KCN. The cyanide ion (CN⁻) acts as a nucleophile and replaces the bromine atom. This results in the formation of **allyl cyanide (C₃H₅CN)**:
```
CH2CN
|
CH
|
CH2
```
The byproduct of this reaction is KBr.

### Conclusion
The final compound C formed after the series of reactions is **allyl cyanide (C₃H₅CN)**.

### Answer
C = Allyl cyanide (C₃H₅CN)

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