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Which of the folliwng haldies can yield ...

Which of the folliwng haldies can yield ethane and also methane in a single step?

A

`C_(2)H_(5)Br`

B

`CH_(2)I`

C

`(CH_(3))_(2)CHBr`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To determine which halide can yield both ethane and methane in a single step, we will analyze the reactions of iodomethane (CH3I). ### Step-by-Step Solution: 1. **Identify the Halide**: The halide in question is iodomethane (CH3I). 2. **Formation of Ethane**: - To produce ethane (C2H6) from iodomethane, we can use the **Wurtz Reaction**. This reaction involves the coupling of alkyl halides in the presence of sodium metal (Na) and an ether solvent. - The reaction can be represented as follows: \[ 2 \, \text{CH}_3\text{I} + 2 \, \text{Na} \xrightarrow{\text{ether}} \text{C}_2\text{H}_6 + 2 \, \text{NaI} \] - Here, two moles of iodomethane react with sodium to form ethane and sodium iodide. 3. **Formation of Methane**: - To produce methane (CH4) from iodomethane, we can react it with red phosphorus (P) and hydrogen iodide (HI). - The reaction can be represented as follows: \[ \text{CH}_3\text{I} + \text{P} + \text{HI} \rightarrow \text{CH}_4 + \text{PI}_3 \] - In this reaction, iodomethane reacts to yield methane along with phosphorus triiodide. 4. **Conclusion**: - Since iodomethane can yield both ethane and methane in separate reactions, it is the correct answer to the question. Therefore, the halide that can yield ethane and methane in a single step is **iodomethane (CH3I)**. ### Final Answer: The halide that can yield ethane and methane in a single step is **iodomethane (CH3I)**. ---

To determine which halide can yield both ethane and methane in a single step, we will analyze the reactions of iodomethane (CH3I). ### Step-by-Step Solution: 1. **Identify the Halide**: The halide in question is iodomethane (CH3I). 2. **Formation of Ethane**: - To produce ethane (C2H6) from iodomethane, we can use the **Wurtz Reaction**. This reaction involves the coupling of alkyl halides in the presence of sodium metal (Na) and an ether solvent. ...
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