The disillation of bleaching powder and acetone gives:

Options

A. `CHCl_(3)`
B. Chloral
C. `CH_(3)Cl`
D. `CCl_(4)`

Explanation

To solve the question regarding the distillation of bleaching powder and acetone, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Components**:
- Bleaching powder is chemically represented as calcium oxychloride (Ca(OCl)₂).
- Acetone is represented as CH₃COCH₃.

2. **Reaction of Bleaching Powder with Water**:
- When bleaching powder is mixed with water, it undergoes hydrolysis to produce calcium hydroxide (slaked lime) and chlorine gas.
- The reaction can be written as:
\[ Ca(OCl)_2 + 2H_2O \rightarrow Ca(OH)_2 + 2Cl_2 \]

3. **Chlorination of Acetone**:
- The chlorine gas produced will react with acetone. The chlorine can replace the hydrogen atoms in acetone.
- The chlorination of acetone can be represented as:
\[ CH_3COCH_3 + 3Cl_2 \rightarrow CHCl_3 + 3HCl \]
- This reaction results in the formation of chloroform (CHCl₃) and hydrochloric acid (HCl).

4. **Reaction of Chloroform with Calcium Hydroxide**:
- The chloroform produced can further react with the calcium hydroxide to yield chloroform and a calcium salt.
- The reaction can be summarized as:
\[ 2CHCl_3 + Ca(OH)_2 \rightarrow 2CHCl_3 + Ca(CH_3COO)_2 \]
- Here, calcium acetate is also formed, but the major product is chloroform.

5. **Conclusion**:
- The primary compound obtained from the distillation of bleaching powder and acetone is chloroform (CHCl₃).

### Final Answer:
The distillation of bleaching powder and acetone gives **chloroform (CHCl₃)**.

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