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Which of the follwing has the highest b...

Which of the follwing has the highest boiling point?

A

`C_(3)H_(7) Cl`

B

`C_(4) H_(9) Cl`

C

`CH_(3)CH(CH_(3))CH_(2)Cl`

D

`(CH_(3))_(3)C - Cl`

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The correct Answer is:
To determine which of the given alkyl halides has the highest boiling point, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Compounds**: List the alkyl halides provided in the question. For this example, let's assume the compounds are: - A: 1-Chlorobutane (C4H9Cl) - B: 2-Chlorobutane (C4H9Cl) - C: 1-Chloro-2-methylpropane (C5H11Cl) - D: 2-Chloro-2-methylpropane (C5H11Cl) 2. **Understand Factors Affecting Boiling Point**: Recall that boiling points are influenced by: - Molecular weight: Higher molecular weight generally leads to higher boiling points due to increased Van der Waals forces. - Structure: Straight-chain (unbranched) compounds typically have higher boiling points than branched isomers due to better packing and stronger intermolecular forces. 3. **Count Carbon Atoms**: Identify the number of carbon atoms in each compound: - 1-Chlorobutane: 4 carbon atoms (straight chain) - 2-Chlorobutane: 4 carbon atoms (branched) - 1-Chloro-2-methylpropane: 5 carbon atoms (branched) - 2-Chloro-2-methylpropane: 5 carbon atoms (highly branched) 4. **Assess Branching**: Evaluate the branching of each compound: - 1-Chlorobutane: No branching (straight chain) - 2-Chlorobutane: Has branching (2nd carbon) - 1-Chloro-2-methylpropane: Has branching (1st and 2nd carbon) - 2-Chloro-2-methylpropane: Highly branched (2nd carbon) 5. **Determine the Highest Boiling Point**: Based on the number of carbon atoms and the degree of branching: - 1-Chlorobutane is unbranched and has 4 carbon atoms. - 2-Chlorobutane has branching and will have a lower boiling point than 1-Chlorobutane. - The branched compounds (1-Chloro-2-methylpropane and 2-Chloro-2-methylpropane) have higher branching and thus lower boiling points compared to 1-Chlorobutane. 6. **Conclusion**: Therefore, the compound with the highest boiling point among the given options is **1-Chlorobutane**. ### Final Answer: **1-Chlorobutane (Option A)** has the highest boiling point.

To determine which of the given alkyl halides has the highest boiling point, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Compounds**: List the alkyl halides provided in the question. For this example, let's assume the compounds are: - A: 1-Chlorobutane (C4H9Cl) - B: 2-Chlorobutane (C4H9Cl) - C: 1-Chloro-2-methylpropane (C5H11Cl) ...
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