Chlorobenzene can be prepared by reacting aniline with

Options

A. Hydrochloric acid
B. Cuprous chloride
C. Chlorine in the presence of anhydrous aluminium chloride
D. Nitrous acid followed by heating with curprous chloride

Explanation

To prepare chlorobenzene from aniline, we can follow these steps:

### Step 1: Diazotization of Aniline
- **Reaction**: Aniline (C6H5NH2) is treated with nitrous acid (HNO2) in the presence of hydrochloric acid (HCl) at a low temperature (0 to 5 degrees Celsius).
- **Product**: This reaction forms benzene diazonium chloride (C6H5N2Cl).

### Step 2: Sandmeyer Reaction
- **Reaction**: The benzene diazonium chloride is then reacted with cuprous chloride (CuCl) in the presence of hydrochloric acid (HCl).
- **Product**: This leads to the substitution of the diazonium group (N2) with a chlorine atom (Cl), resulting in the formation of chlorobenzene (C6H5Cl).

### Final Reaction Summary
- The overall process can be summarized as:
1. Aniline + HNO2 + HCl → Benzene diazonium chloride
2. Benzene diazonium chloride + CuCl + HCl → Chlorobenzene + N2 (gas)

### Conclusion
The correct answer to the question is that chlorobenzene can be prepared by reacting aniline with **nitrous acid followed by cuprous chloride**.

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