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The compound that will react most readil...

The compound that will react most readily with NaOH to form methanol is :

A

`(CH_(3))_(4) overset(o+)(N)I^(theta)`

B

`CH_(3)OCH_(3)`

C

`(CH_(3))_(3) S^(o+) I^(theta)`

D

`(CH_(3))_(3)Cl`

Text Solution

Verified by Experts

The correct Answer is:
`a`
`EN` of `N gt S`.
Positive charge on `N` will make `(Me)` group more `overline(e)` deficient than positive charge on `S`. Therefore (a) will undergo `SN^(2)` reaction more rapidly than (c).
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