Given that at 1000K `2SO_2 (g)+O_(2)(g) Leftrightarrow 2SO_(3)(g), " "K=261`
Calculate K for the following equations:
(i) `2SO_(3) (g) Leftrightarrow 2SO_(2) (g)+O_(2)(g)`
(ii) `SO_(3)(g) Leftrightarrow SO_(2)(g)+1/2 O_(2) (g)`
(iii) `SO_(2) (g)+1/2 O_(2) (g) Leftrightarrow SO_(3) (g)`

Explanation

Equation (i) is the reverse of the given equation `K=1/(261)=0.0038" (for (i)). ……………(Eqn.5)"`
As the equation (ii) has been obtained by dividing the equation (i) by 2, K for the equation (ii) will be `(0.0038)^(1/2)=0.0619……….("Eqn 6")`
Reversing the equation (ii) we get the equation (iii), K for which will be `(1)/(0.0619)=16.155`