At `427^@C`, for the gaseous reaction
`H_2+I_2=2HI, K=55`
(a) What weight of HI will be formed at equilibrium if 1 mole of `H_2` and 1 mole of iodine are placed in a 1-litre vessel at `427^@C?`
(b) Will there be any reaction at `427^@C` in a mixture consisting of 0.07 atm of HI and 0.02 atm of each of `H_2 and I_2?` If so, will HI be consumer or formed? (I=127, H=1).

Explanation

To solve the problem, we will break it down into two parts as per the question.

### Part (a): Weight of HI formed at equilibrium

1. **Write the balanced equation**:
\[ H_2(g) + I_2(g) \rightleftharpoons 2HI(g) \]
...