When alcohol `(C_(2)H_(5)OH)` and acetic are mixed together in equimolecular proportions at `25^@C` 66.5% is converted into ester. Calculate how much ester will be formed if 1 mole of acetic acid is treated with 0.5 mole of alcohol at the same tempearture.

Explanation

To solve the problem of how much ester will be formed when 1 mole of acetic acid reacts with 0.5 moles of ethyl alcohol (C₂H₅OH), we can follow these steps:

### Step 1: Understand the Reaction
The reaction between acetic acid (CH₃COOH) and ethyl alcohol (C₂H₅OH) produces an ester (ethyl acetate, CH₃COOC₂H₅) and water (H₂O). The balanced chemical equation for the reaction is:

\[ \text{CH}_3\text{COOH} + \text{C}_2\text{H}_5\text{OH} \rightleftharpoons \text{CH}_3\text{COOC}_2\text{H}_5 + \text{H}_2\text{O} \]

### Step 2: Initial Moles
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