The dissociation of solid `NH_4HS` in a closed container produces a pressure of 1.12 atm at `105^@C`. Calculate `K_p` for the equilibrium. `NH_(4)HS (s) Leftrightarrow NH_(3) (g)+H_(2)S(g)`

Explanation

To calculate \( K_p \) for the equilibrium of the dissociation of solid \( NH_4HS \), we can follow these steps:

### Step 1: Write the balanced equation for the dissociation
The dissociation of solid ammonium hydrogen sulfide can be represented as:
\[ NH_4HS (s) \rightleftharpoons NH_3 (g) + H_2S (g) \]

...