If the heat of reaction at constant volume exceeds that at constant pressure for an Kp. endothermic reaction at `25^@C` by 1190 cal, what is the value of the ratio `K_(p)/(K_(c)?`

Explanation

To solve the problem, we need to find the value of the ratio \( \frac{K_p}{K_c} \) for an endothermic reaction given that the difference between the heat of reaction at constant volume and at constant pressure is 1190 cal.

### Step-by-Step Solution:

1. **Understanding the Relationship Between Enthalpy and Internal Energy**:
The relationship between the change in enthalpy (\( \Delta H \)) and the change in internal energy (\( \Delta E \)) for a reaction can be expressed as:
\[
\Delta H - \Delta E = \Delta N \cdot R \cdot T
...