The ionisation constant of `NH_(4)^+` in water is `5.6 xx 10^(-10)" at "25^@C`. The rate constant for the rection of `NH_(4)^+ and OH^-` to form `NH_(3) and H_(2)O" at "25^@C 3.4 xx 10^(10)" L mol"^(-1) s^(-1)`. Calculate the rate constant for proton from water to `NH_(3)`.

Explanation

To solve the problem, we need to calculate the rate constant for the proton transfer from water to ammonia (NH₃). We will use the given ionization constant (Kₐ) for the ammonium ion (NH₄⁺) and the rate constant (k) for the reaction of NH₄⁺ with hydroxide ions (OH⁻).

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Ionization constant of NH₄⁺ (Kₐ) = 5.6 × 10⁻¹⁰
- Rate constant for the reaction of NH₄⁺ and OH⁻ (k) = 3.4 × 10¹⁰ L mol⁻¹ s⁻¹

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