The ionisation constant `K_(b)` for hydrazine `(N_(2)H_(4))" is " 9.6 xx 10^(-7)`. What would be the % age hydrolysis of `0.001 M N_(2)H_(5)Cl`, a salt containing acid ion conjugate to hydrazine base.

Explanation

`N_(2)H_(5)^(+)+H_(2)O Leftrightarrow N_(2)H_(4)+H_(3)O^(+)`
`K_(h)=(K_(w))/(K_(b))=(1 xx 10^(-14))/(9.6 xx 10^(-7))=1.04 xx 10^(-8)`
`h=sqrt(K_h/c)=sqrt((1.04 xx 10^(-8))/(0.10))=3.225 xx 10^(-4)`
per cent hydrolysis =0.03225%.