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2.05 g of sodium acetate was added to 10...

2.05 g of sodium acetate was added to 100 mL of 0-1 M HCl solution. Find the `H^+` ion concentration of the resulting solution. If 6 mL of 1 M HCl is further added to it, what will be the new H concentration?

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The correct Answer is:
`1.23 xx 10^(-5)M, 1.36 xx 10^(-5)M`
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