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The volume of water needed to dissolve 1...

The volume of water needed to dissolve 1g of `BaSO_4 (K_(sp)= 1.1 xx 10^(-10))" at 25"^@C` is

A

820 litres

B

450 litres

C

205 litres

D

none of these

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The correct Answer is:
To solve the problem of how much water is needed to dissolve 1 g of barium sulfate (BaSO₄) given its solubility product constant (Ksp), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Dissociation of BaSO₄**: When barium sulfate dissolves in water, it dissociates into barium ions (Ba²⁺) and sulfate ions (SO₄²⁻): \[ \text{BaSO}_4 (s) \rightleftharpoons \text{Ba}^{2+} (aq) + \text{SO}_4^{2-} (aq) \] 2. **Set Up the Expression for Ksp**: The solubility product constant (Ksp) is given by the equation: \[ K_{sp} = [\text{Ba}^{2+}][\text{SO}_4^{2-}] \] If we let the solubility of BaSO₄ be \( s \) (in moles per liter), then: \[ K_{sp} = s \cdot s = s^2 \] 3. **Substitute the Given Ksp Value**: Given \( K_{sp} = 1.1 \times 10^{-10} \): \[ s^2 = 1.1 \times 10^{-10} \] 4. **Calculate the Solubility (s)**: To find \( s \), take the square root of both sides: \[ s = \sqrt{1.1 \times 10^{-10}} \approx 1.05 \times 10^{-5} \text{ moles/L} \] 5. **Calculate the Molar Mass of BaSO₄**: The molar mass of BaSO₄ is calculated as follows: - Barium (Ba): 137.33 g/mol - Sulfur (S): 32.07 g/mol - Oxygen (O): 16.00 g/mol × 4 = 64.00 g/mol \[ \text{Molar mass of BaSO}_4 = 137.33 + 32.07 + 64.00 = 233.40 \text{ g/mol} \] 6. **Convert Solubility to Grams**: Now, we can convert the solubility in moles to grams: \[ \text{mass of BaSO}_4 = s \times \text{molar mass} = (1.05 \times 10^{-5} \text{ moles/L}) \times (233.40 \text{ g/mol}) \approx 2.45 \times 10^{-3} \text{ g/L} \] 7. **Calculate the Volume of Water Needed**: To find the volume of water needed to dissolve 1 g of BaSO₄, we can use the relationship: \[ \text{Volume} = \frac{\text{mass of BaSO}_4}{\text{mass concentration}} = \frac{1 \text{ g}}{2.45 \times 10^{-3} \text{ g/L}} \approx 408.16 \text{ L} \] ### Final Answer: The volume of water needed to dissolve 1 g of BaSO₄ is approximately **410 liters**.
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