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Find the derivative of y=2x^2+4x^-1/2-3x...

Find the derivative of y=`2x^2+4x^-1/2-3x^-2`

Text Solution

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`y=x^7/2`
`dy/dx=d/dx(2x^2+4x^-1/2 -3x^-2)`
`=d/dx(2x^2)+d/dx(4x^-1/2)-d/dx(3x^-3`)
`=2xx2x+4(-1/2)x^(1-1/2) -3 xx(-2)x^-2-1=4x-2x^-3/2+6x^-3`
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