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The height reached in time t by a partic...

The height reached in time t by a particle thrown upward with a speed u is given by
`h=ut-1/2``g``t^2`
where `g=9.8 m/s^2` is a constant. Find the time taken in reaching the maximum height.

Text Solution

Verified by Experts

`vecA=5vecI+vecj -2veck`
`absvecA=sqrt(5^2+(1)^2+(-2))=sqrt30`
Required unit vector `vecA/abs vecA =1/sqrt30(5veci+vecj-2veck)`
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