A particle is moving with uniform acceleration.its displacement at any instant t is given by `S= 10t+4.9t^2`. What is its Initial velocity

A particle moves with uniform acceleration and the distance travelled in t - th second is s_(t) = 3 + 2t . Find the initial velocity of the particle .

Statement I : A particle moving with uniform acceleration has its displacement proportional to the square of time. Statement II : If the motion of a particle is represented by a straight line on the velocity -time graph its acceleration is uniform.

A particle moves along X-axis and its displacement at any time is given by x(t) = 2t^(3) -3t^(2) + 4t in SI units. The velocity of the particle when its acceleration is zero, is

A particle is moving with a uniform acceleration along a straight line AB. Its velocity at A and B are 2 m/s and 14 m/s respectively. Then

A body is moving from rest with an acceleration a m . s^(-2) which is related to time t s by a = (3t +4) . What will be its velocity in time 2 s?

For a body moving with a uniform acceleration, prove that its average velocity is the arithmetic mean of its initial and final velocities.

A particle, starting from rest, is in uniform acceleration. Its displacement in (P- 1) seconds and P seconds are s_(1) and s_(2) respectively . Then what would be its displacement in the (P^(2)-P+1) -th second?

A partical is moving along the x-axis. The position of the partical at any instant is given by x = a+ bt^(2) where, a = 6 m and b = 3.5 "m.s"^(-2) ,t is measured in second. Find the average velocity between t = 3s and t = 6 s.

The velocity of a particle (v) at an instant 't' is given by v = at + bt^(2) , the dimension of b is

The distance-time graph of a moving particle is given by x = 4t -6t^(2) . What is the positive maximum speed?