Write the dimensions of `a xx b` in the relation `E = ( b - x^(2))/( at)`, where `E` is the energy , `x` is the displacement , and `t` is the time.

What will be the dimension of (a)/(b) in the equation p =(a-t^(2))/(bx) ? Here p = pressure x = distance and t = time.

y = (ax + b) e^(-2x)

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation t = sqrt(x+3) where x is in meters and t is in seconds. Finds the displacement (in metres ) of the particle when its velocity is zero.

If P = pressure, X = distance, t = time in the equation P = (a - t^2)/bx that what is the dimension of a/b

The equation of an SHM is x=8 sin omega t + 15 cos omega t , where x is displacement and t is time . The amplitude will be

Find out the dimension of (GIM^(2))/(E^(2)) where E = energy G = gravitational constant I =impulse of force and M = mass.

The equation x= A sin omega t gives the relation between the time t and the corresponding displacement x of a moving particle where A and omega are constant. Prove that the acceleration of the particle is proportional to its displacement and is directed opposite to it.

If x = a+bt+ ct^(2) , where x is in metres and t in seconds what are the dimensions of b and c?