The resistance `R = V//i`, where `V = 100 +- 5 V and I = 10+- 0.2 A`. What is the total error in `R`?

Two resistances are expressed as R_1=(4 ±0.5) Omega and R_2 =(12 ±0.5) Omega . What is the net resistances when these are connected in parallel with percentage error.

To determine an unknown resistance R in the Iaboratory, readings of potentiaI difference V and eIectric current I are taken. From these readings percentage error is caIcuIated and V and I are obtained as V= (100 pm 5) volt I = (10 pm 0.2) amp. The percentage error in the value of R determined from these V and I will be

Statement I : The coil resistance of a 200 V - 100 w electric fan is 20 Omega . A power of 5 W is lost as heat when the fan rotates its maximum speed . Statement II : If , for an electrical device the current is I and the termina potential difference is V , the power consumed - VI .

The internal resistance of a battery of 100 V is 5 Omega . When the emf of the battery is measured by a voltmeter 20% error is found. What is the resistance of the voltmeter?

In a seris LCR circuit R=1kOmega,C=2muF and potential difference across R is 2V. At resonance omega=200rad.s^-1 . What is the potential difference (in V) across L at resonance?

If a heater is connected to 100 V , the power delivered is 100 W . Connecting 10Omega resistance in series with the heater and a resistance to the same 100 V line .waht should be the value of R to obtain 62.5 W power in the heater ?

What is the minimum number of cells each of emf 10 V and internal resistance 1 Omega to pass a current of 10 A through a resistance R of 3 Omega ? What is the discharging power of R?

A battery of emf 1.4V and interna! resistance 2Omega is connected to a resistor of 100Omega resistance through an ammeter. The resistance of ammeter is 4/3Omega a voltmeter has also been connected to find the potential difference across the resistor. The voltmeter reads 1.10V. What is the error in the reading ?