Two resistances are expressed as `R_1=(4 +-0.5)` Omega and `R_2 =(12 +-0.5) Omega` . What is the net resistances when these are connected in series.

Two resistances are expressed as R_1=(4 ±0.5) Omega and R_2 =(12 ±0.5) Omega . What is the net resistances when these are connected in parallel with percentage error.

The vaIue of two resistors are (5.0 pm 0.2)k Omega and (10.0 pm 0.1)k Omega . What is the percentage error in the equivaIent resistance when they are connected in paraIIeI?

Two cells having emf l.5Vand 2V have internal resistance 0.2 Omega and 0.3 Omega respectively. What is the equivalent emf and equivalent resistance if they are connected in paralleled combinations?

To the parallel combination of two resistances 3 Omega and 1 Omega , a series combination of resistances 2.15 Omega and 1 Omega and a battery are connected. The interval resistance of the battery is 0.1 Omega and the emf is 2V. Determine the values of current flowing through the resistances. Draw the diagram of the circuit.

48 similar cells each of emf 1.5V and internal resistance 2 Omega are used for sending current through a resistance of 6 Omega . What will be the current if the cells are connected in the following way: 4 rows and 12 cells in a row

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?

A resistor of magnitude 45 Omega is connected to an electric cell of emf 12V and of 3 Omega internal resistance. An ammeter of resistance 4.5 Omega and a voltmeter of resistance 405 Omega are properly connected with the resistor.What percentage errors is flowing current and potential difference will occur?

What percent will be the equivalent resistance of two resistances 2 Omega and 3 Omega in their parallel combination with respect to their equivalent resistance in series combination?

An electric cell is sending electric currents through a resistance of 10 Omega . IF a shunt of 1 Omega is connected with that resistance then the current through the 10 Omega resistance becomes half of the previous value.What is the resistance of the cell?IF the current through the shunt be 0.9A, then what will be the emf of the cell?