Two resistances are expressed as `R_1=(4 ±0.5) Omega` and `R_2 =(12 ±0.5) Omega` . What is the net resistances when these are connected in parallel with percentage error.

Two resistances are expressed as R_1=(4 +-0.5) Omega and R_2 =(12 +-0.5) Omega . What is the net resistances when these are connected in series.

The vaIue of two resistors are (5.0 pm 0.2)k Omega and (10.0 pm 0.1)k Omega . What is the percentage error in the equivaIent resistance when they are connected in paraIIeI?

Two cells having emf l.5Vand 2V have internal resistance 0.2 Omega and 0.3 Omega respectively. What is the equivalent emf and equivalent resistance if they are connected in paralleled combinations?

A resistor of magnitude 45 Omega is connected to an electric cell of emf 12V and of 3 Omega internal resistance. An ammeter of resistance 4.5 Omega and a voltmeter of resistance 405 Omega are properly connected with the resistor.What percentage errors is flowing current and potential difference will occur?

Equivalent resistance are 12Omega and 2.25Omega when two resistors are connected in series and parallel. Calculate the value of resistors.

To the parallel combination of two resistances 3 Omega and 1 Omega , a series combination of resistances 2.15 Omega and 1 Omega and a battery are connected. The interval resistance of the battery is 0.1 Omega and the emf is 2V. Determine the values of current flowing through the resistances. Draw the diagram of the circuit.

R_1 and R_2 are two resistances they are connected in parallel combinations Write down their equivalent resistance in each case.

R_1 and R_2 are two resistances they are connected in series Write down their equivalent resistance in each case.

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?

A cell has an emf of 3V and an internal resistance r. The circuit current is 0.75A when it is connected to an external resistance of 1 Omega . IF the poles are connected directly what will be the current (in A)?