A body of mass 0.5 kg travels in a straight line with velocity v=`ax^(3//2)` where a=`5m^(-1/2)s^(-1)` . What is the work done by the net force during its displacement from =0 to x=2m?

A particle of mass 0.5 kg travels in a straigh line with a velocity v =5x^(5//2)m*s^(-1) . How much work is done by the net force during the displacement from x=0 to x=2 m ?

A body of mass 10 kg is raised by 5m . What is the work done ?

The velocity of a moving body of mass m along positive x axis is V = asqrtx (a = constant). Find the work done by the force applied on the body to displace it from x = 0 to x = 1.

The velocity of a moving body of mass m along positive.x axis is v =a sqrt(x) (a=constant). Find the work done by the force applied on the body to displace it from x=0 to x=l.

A body of mass 3 kg acted upon by a constant force is displaced by 's' meter, given by the relation s=(1)/(3)t^(2) , where t is in second. Work done by the force in 2 seconds is

The velocity of a moving body of mass m along positive x axis is nu = asqrtx (a= constant). Find the work done by the force applied on the body to displace it from x = 0 to x = l.

A body of mass 6 kg is acted upon by a force which causes a displacement in it given by x = t^2/4 meter, where t is the time in second. The work done by the force in 2 seconds is

A body of mass 10 kg is raised to a height of 10 m with an upward force of 196 N . Find the work done by the upward force and the work done against gravitation. Show that the total energy in this case is equal ot the work done by the upward force . [g=9.8 m*s^(-2) ]