Two particles of masses 3 kg and 2kg are located at `(-6hati+4hatj-2hatk)` and `(2hati+5hatj+13hatk)` respectively. Locate the position of centre of mass.

Velocity of two objets of mass 10 kg and 2 kg is (2hati-7hatj+3hatk) m//s and (-10hati+35hatj-3hatk) m//s respectively. Calculate the velocity of their centre of mass.

The position vector of two masses of 6 unit and 2 unit is (6hati-7hatj) & (2hati + 5hatj) respectively. Find out the position of their centre of mass.

Two objects of mass 10 kg and 2kg are moving with velocities (2hati-7hatj+3hatk) m//s and (-10hati+35hatj-3hatk) m/s respectively. Calculate the velocity of the centre of mass of the system.

In a system comprising of two particles of mass 2 kg and 5 kg, the positions of the two particles at t=0 are (4hati+3hatj) and (6hati-7hatj+7hatk) respectively and the velocities are (10hati-6hatk) and (3hati+6hatj) respectively. Deduce the velocity of the centre of mass and the position of the centre or mass at t=0 and t=4 s

Two objects of 3 kg & 1 kg have position vectors (-6hati + 4hatj-2hatk) & (2hati +5hatj+13hatk) . What is its centre of mass?

The position vectors of the three vertices of a triangle are (-hati-3hatj+2hatk), (5hati+7hatj-5hatk) and (2hati+5hatj+6hatk) , then the position vector of the point of intersection of the medians of the triangle is -

The position vectors of the vertices A,B,C of the triangle ABC are (hati+hatj+hatk),(hati+5hatj-hatk) and (2hati+3hatj+5hatk) respectively. Find the greatest angle of the triangle.

The position vectors of points A,B and C are hati+hatj+hatk,hati + 5hatj -hatk and 2hati + 3hatj + 5hatk , respectively the greatest angle of triangle ABC is

A vector perpendicular to both of (3hati+hatj+2hatk) and (2hati-2hatj+4hatk) is

The position vectors of the points A, B, C and D are hati+3hatj-hatk, -hati-hatj+hatk, 2hati-3hatj+3hatk and -3hati+2hatj+hatk respectively. Then, the ratio of the moduli of the vectors vec(AB) and vec(CD) is -